4.9x^2-15x+5=0

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Solution for 4.9x^2-15x+5=0 equation: 



4.9x^2-15x+5=0

a = 4.9; b = -15; c = +5;
Δ = b2-4ac
Δ = -152-4·4.9·5
Δ = 127
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{127}}{2*4.9}=\frac{15-\sqrt{127}}{9.8}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{127}}{2*4.9}=\frac{15+\sqrt{127}}{9.8}
$

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